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Simplifying 2c2 + 4c = c2 + 5 Reorder the terms: 4c + 2c2 = c2 + 5 Reorder the terms: 4c + 2c2 = 5 + c2 Solving 4c + 2c2 = 5 + c2 Solving for variable 'c'. Reorder the terms: -5 + 4c + 2c2 + -1c2 = 5 + c2 + -5 + -1c2 Combine like terms: 2c2 + -1c2 = 1c2 -5 + 4c + 1c2 = 5 + c2 + -5 + -1c2 Reorder the terms: -5 + 4c + 1c2 = 5 + -5 + c2 + -1c2 Combine like terms: 5 + -5 = 0 -5 + 4c + 1c2 = 0 + c2 + -1c2 -5 + 4c + 1c2 = c2 + -1c2 Combine like terms: c2 + -1c2 = 0 -5 + 4c + 1c2 = 0 Factor a trinomial. (-5 + -1c)(1 + -1c) = 0Subproblem 1
Set the factor '(-5 + -1c)' equal to zero and attempt to solve: Simplifying -5 + -1c = 0 Solving -5 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1c = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1c = 0 + 5 -1c = 0 + 5 Combine like terms: 0 + 5 = 5 -1c = 5 Divide each side by '-1'. c = -5 Simplifying c = -5Subproblem 2
Set the factor '(1 + -1c)' equal to zero and attempt to solve: Simplifying 1 + -1c = 0 Solving 1 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1c = 0 + -1 -1c = 0 + -1 Combine like terms: 0 + -1 = -1 -1c = -1 Divide each side by '-1'. c = 1 Simplifying c = 1Solution
c = {-5, 1}
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